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View Code? Open in Web Editor NEWA simple HTN planner based around the principles of the Builder pattern.
License: MIT License
A simple HTN planner based around the principles of the Builder pattern.
License: MIT License
hi,
I needed a C++ HTN and ran across your project while searching. Since I found the code easy to follow and you have a ton of Unit tests, I was able to convert it to C++.
It lives here https://github.com/accesshoops/fluid-hierarchical-task-network
I converted most of the Unit Tests to C++ as well and am trying to get the TextAdventure working in C++ too. That part is here https://github.com/accesshoops/fluid-text-adventure
My eventual goal is to have an UE4 example project, but that will probably take a while longer.
If you'd like to take a look at my fork and consider integrating it with this project, let me know. I totally understand if you don't want to deal with a whole another language :-) .
Edit: TextAdventure needs more work.
Hello and many thanks for your work
By installing Callback hooks in the planner;
I try to get last state from any task (for debugging purposes)
But apparently (If i understood well) ITask.LastStatus is never updated internally by any class derived from ITask
Thanks
Describe the bug
Base on the Humphreys' article, MTR with a lower index should have higher priority.
To Reproduce
For example:
ctx.LastMTR: [0, 3, 0]
ctx.MethodTraversalRecord: [0, 0]
taskIndex = 1
Expected behavior
[0,0,1] should have a higher priority than [0,3,0].
Describe the bug
Domain.FindPlan(...)
rejects valid new plan, because the MethodTraversalRecord
equals the LastMTR
, even though the found plan differs from the last found plan.
To Reproduce
Define a domain like this (where OperatorA
and OperatorB
are both operators that do NOT finish instantly):
.Select("Test Select")
.Action("Test Action A")
.Condition("Can choose A", ctx => ctx.HasState(TestWorldState.CanChooseA))
.SetOperator(new OperatorA())
.End()
.Action("Test Action B")
.Condition("Can not choose A", ctx => !ctx.HasState(TestWorldState.CanChooseA))
.SetOperator(new OperatorB())
.End()
.End()
Then set TestWorldState.CanChooseA
to true
and Tick()
the planer. Observe (as expected) that a plan containing only "Test Action A" is found.
Then (while the existing plan is not yet finished) set TestWorldState.CanChooseA
to false
and Tick()
the planer again. Observe that the plan containing only "Test Action B" is initially found during the decomposition but is then discarded by this part of the code:
// If this MTR equals the last MTR, then we need to double check whether we ended up
// just finding the exact same plan. During decomposition each compound task can't check
// for equality, only for less than, so this case needs to be treated after the fact.
var isMTRsEqual = ctx.MethodTraversalRecord.Count == ctx.LastMTR.Count;
if (isMTRsEqual)
{
for (var i = 0; i < ctx.MethodTraversalRecord.Count; i++)
if (ctx.MethodTraversalRecord[i] < ctx.LastMTR[i])
{
isMTRsEqual = false;
break;
}
if (isMTRsEqual)
{
plan = null;
status = DecompositionStatus.Rejected;
}
}
because both the MethodTraversalRecord
and the LastMTR
are equal and contain only the single entry 0
, even though the new plan (containing only "Test Action B") is different from the old plan (containing only "Test Action A").
Expected behavior
The new plan should not have been rejected for being equal to the old plan because it is clearly different.
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