gpsinghsandhu / background-subtraction-using-gmm

This project is the C++ implementation of Background Subtraction using adaptive GMM models as discussed by Zoran Zivkovic in his paper "Improved Adaptive Gaussian Mixture Model for Background Subtraction".

Background-Subtraction-using-GMM

REQUIREMENTS:

• Any C++ compiler (originally developed in visual studio, thus remove conio.h and _getch to be able work on other enviroment)
• OpenCV 2.2 or above (originally developed on OpenCV 2.3.1)

This project is the C++ implementation of Background Subtraction using adaptive GMM models as discussed by Zoran Zivkovic in his paper "Improved Adaptive Gaussian Mixture Model for Background Subtraction".

This project was developed as a part of learning about the computer vision and thus gives (though very basic) an efficient and accurate implementation of the above mentioned algorithm. It uses OpenCV just for the data acquisition and preprocessing and its 'Mat' object for susequent processing. Following which is an implementation for the GMM models as discussed in the paper.

The testing data has also been provided with the project. It is a part of the PETS 2009 dataset.

Note: This project was developed on the basis of my undrstanding of the paper and thus must not considered an exact implementation of the project.

Check out the result video - http://youtu.be/QwmX3U78K6A

background-subtraction-using-gmm's Issues

Can not find file

I can not find file #include <opencv2\Blob_detection.hpp>, it make an error.

N_ptr was nullptr

Hello, I am running the code in Visual Studio 2017 in Debug mode. The code builds successfully, however when I run it I get this error:
line 302 start = N_ptr->pixel_s; --> Exception thrown: read access violation. N_ptr was nullptr.

How can I solve?

Thank you

why "*(r_ptr++);" stands for R,

A quick glance at the precedence table for operators will tell you that postfix increment has a higher precedence (16) than dereference / indirection (15). This means that the complex expression *p++ is going to be grouped as: *(p++). That is to say, the * part will be applied to the value of the p++ part. So let's take the p++ part first.

rVal = *(r_ptr++);
gVal = *(r_ptr++);
bVal = *(r_ptr++);

https://stackoverflow.com/questions/18481740/pointer-expressions-ptr-ptr-and-ptr