zhaozhentao / kugoulayout Goto Github PK
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License: MIT License
an interesting layout
License: MIT License
我觉得项目实在太复杂了,其实我觉得可以简单化。
下面是我的一些简单的想法
酷狗的中心旋转点,应该是在X= width * 0.5f,Y = height * 1.5f。然后根据第一次的触摸点,计算触摸点与旋转中心的夹角角度 A(如果角度为负数,则A = A+180),同理再计算最后一次的触摸点与旋转中心的夹角角度 B(如果角度为负数,则B = B+180)。最后,计算旋转的角度 D = B - A。即可
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