A Wordle Solver console application using C++ by an easy yet efficient algorithm.
- Code Blocks (IDE)
- C++
- STL library
For each bad letter (aka black letter) put '!' before it. For each possible letter (aka yellow letter) put '@' before it. For each right letter (aka green letter) put '#' before it.
Example:
!n@o#t!e!s
where: n,e,s are black, o is yellow, t is green
Don't put spaces between letters as input.
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Populate vector named 'v' with words inside the dictionary using "populateVector" function
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Take input from user
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If the letter in the word is Green, insert it in "rightLetters" vector along with its index. If the letter is Yellow, insert it in "possibleLetters" vector along with its index.
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If the letter is black, we will check if it has been previously inserted in right or possible vector, if so we will insert it in "specialLetters" vector, else we will inser it in "badLetters" vector.
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For each Bad letter in the word (Black Letter):
Iterate through the vector of words, if any word contain such bad letter, remove it from vector
void eliminateBadLetters(char x){ //removing words containing black characters
for(it=v.begin();it!=v.end();){
bool flag =false;
string temp = *it;
for(int i=0;i<=4;i++){
if(x==temp[i]){
flag =true;
break;
}
}
flag?it=v.erase(it):++it;
}
}
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For each Possible letter in the word (Yellow Letter):
Iterate through vector of words If any words doesn't contain that yellow character at all, remove it If any word has yellow character in the same position as entered in input, remove it.
void eliminatePossibleLetters(char x,int y){
for(it=v.begin();it!=v.end();){ //removing any word which does not have yellow character in right position
string temp =*it;
temp[y]==x?it = v.erase(it):++it;
}
for(it =v.begin();it!=v.end();){ //removing any word which does not have any yellow character at all
string temp =*it;
bool flag =false;
for(int k=0;k<=4;k++){
if(x==temp[k]){
flag =true;
break;
}
}
flag?++it:it=v.erase(it);
}
}
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For each Right letter (Green Letter):
Iterate through vector of words, if any word doesn't have that character in same position as entered, remove it.
void findRightLetters(char x,int y){
for(it = v.begin();it!=v.end();){ //removing any word which does not have green character in right position
string temp = *it;
temp[y]!=x?it = v.erase(it):++it;
}
}
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For each (Special letter):
Iterate through vector of words, if any word have that character in same position as entered, remove it.
void eliminateSpecialLetters(char x,int y){
for(it = v.begin();it!=v.end();){
string temp = *it;
temp[y]==x?it = v.erase(it):++it;
}
}
Special letter are the letters which are green and (black) at the same time. Meaning special letters are just black letters with index.