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linear-algebra-left-undone's Issues

关于下载的问题

github
我在下载讲义,进行到这一步的时候出现这种问题,请问如何解决,拜托大佬,我是个高中生,虚心请教!!

关于“构造性证明”的讨论

预备**章节中用这个命题作为非构造性证明的例子:
$$
证明:存在无理数 $x, y$ 使得 $x^y$ 为有理数.
假定 $\sqrt{2}^{\sqrt{2}}$ 为有理数,则原命题得证;假定其为无理数,则 $\left(\sqrt{2}^{\sqrt{2}}\right)^{\sqrt{2}}$ 为有理数,原命题仍得证.
$$
我感觉这个不能算是严格的非构造性证明了,因为还是构造出了一个具体的数,只是没有对这个数是否是有理数做出定论。严格意义上非构造性证明应该是不依赖于具体的什么例子的。

188页图示可能引发误解

容易把向量和坐标混淆起来,向量本身不会随着坐标变换而改变,但是坐标会;它们两个对于任意映射相同是在F^m,F^n的自然基下讨论的。
在之前丹青辅学的时候遇到过有同学有这个疑问。

107页例5.8小bug

v0.4版107页例5.8中的“连续函数”应改为“光滑函数”,毕竟该例中的线性空间V要求对求导运算封闭

13讲 行列式 小语病

在公理化定义中,我们将行列式定义为一个满足特定的运算性质的从列向量组合到数的函数. 事实上,公理化定义从是逆序数定义可以推导出的行列式的运算性质,教材采用这种定义避开了繁琐的说明.

应从公理化定义从是逆序数定义可以推导出的改为公理化定义是可以从逆序数定义推导出的

参考文献一处链接不太对劲

是蓄意为之吗🥺

最后如果读者学完本讲义后对代数学有浓厚的兴趣,非常推荐读者学习后续的抽象代数课程。这里推荐与我同级的图灵班同学编写的\href{https://frightenedfoxcn。github。io/notes/series/alg-for-cs/}{《写给计算机系学生的代数》}作进一步的了解,我们许多高级专题都对这一讲义有引用。

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