Comments (2)
I think this is not a bug. When you do var b1 = repeat([{}], 2)
, the 2 copies of dict are references to the same space in memory. It is the same dict backing the two references. This is how it works in python also. In the first case (a1), things are assigned by value (not reference).
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I think this is not a bug. When you do
var b1 = repeat([{}], 2)
, the 2 copies of dict are references to the same space in memory. It is the same dict backing the two references. This is how it works in python also. In the first case (a1), things are assigned by value (not reference).
Thanks, I'm not good at python
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