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Ejercicio 6 backtracking implementación
Ejercicio 6 implementación en código de la función
La definición recursiva me quedó igual, así que en principio no encontré algo nuevo que agregar. Acerco la implementación recursiva que hice mientras preparo el recuperatorio.
type Pedido = tuple
id: nat
cost_a: nat
cost_b: nat
value: nat
end tuple
{- Parámetros:
p: arreglo de pedidos,
i: iésimo pedido considerado,
j: materia prima A disponible,
k: materia prima B disponible
-}
fun valor(p: array [1..n] of Pedido, i: nat, j: nat, k: nat) ret v: nat
if i = 0 then
v := 0
else if p[i].cost_a > j or p[i].cost_b then
v := -inf
else
v := max(p[i].value + valor(p, i - 1, j - p[i].cost_a, k - p[i].cost_b),
valor(p, i - 1, j, k)
)
fi
endfun
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