mingyitianxia / elastic-certified-engineer

Path to become an Elasticsearch Certified Engineer

Path to become an Elasticsearch Certified Engineer

The most comprehensive learning resources of the entire network of elasticsearch certified engineers.

Elasticsearch Certified Engineer Exam Preparation Guide.

The shortest path passes the Elasitcsearch certification exam.

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elastic-certified-engineer's Issues

6.2 中对更新父子文档的调整

更新父子文档需要调整routing，但是普通的script不可以更新文档的routing，所以必须在reindex的时候script指定routing，或者在update_by_query的时候使用pipeline的script更新文档的routing

PUT _scripts/init_lines
{
  "script": {
    "lang": "painless",
    "source": """
              HashMap map = new HashMap();
              map.name = 'line';
              map.parent = params.characterId;
              ctx._source.character_or_line = map;
              """
  }
}
PUT _ingest/pipeline/set_routing
{
  "processors": [
    {
      "script": {
        "source": """
              ctx._routing = 'C0';
              """
      }
    }
  ]
}
POST hamlet_3/_update_by_query?pipeline=set_routing
{
  "script": {
    "id": "init_lines",
    "params": {
      "characterId": "C0"
    }
  },
  "query": {
    "match": {
      "speaker": "HAMLET"
    }
  }
}

node.attr属性是否有误按照题目要求是不是应该是AZ

elastic-certified-engineer/review-practice/002_module_01

Line 120 in 9b407dc

node.attr.rack_id: earth

8.1 最后一句选择数组最小的排序

picking the lowest value of the array
应该指定下 mode

GET kibana_sample_data_ecommerce/_search
{
  "query": {
    "match": {
      "day_of_week": "Monday"
    }
  },
  "sort": [
    {
      "products.base_price": {
        "order": "desc",
         "mode": "min"
      }
    }
  ]
}

force.zone.values是否应该和awareness.attributes一致

elastic-certified-engineer/review-practice/002_module_01

Line 130 in 9b407dc

cluster.routing.allocation.awareness.force.zone.values: earth,mars

cluster.routing.allocation.awareness.force.zone.values: earth,mars => cluster.routing.allocation.awareness.force.rack_id.values: earth,mars

0011_zhenti的一些疑问

1）cat & dog那道问题，用mapping char filter把cat and dog和cat & dog都映射成一个特殊字符，例如_catdog_，也能实现，不过适用范围很窄。。
2）04聚合实现，是不是对应the month and average magnitude of the month with the lagest average magnitude?
是否也可以用bucket_sort，对avg_mags进行desc排序，size:1来实现？
3）05，index_a reindex到index_b，是否少了一个管道?
题目是增加一个数组字段，a_pipeline里是把title变成了数组类型
PUT _ingest/pipeline/new_pipeline
{
"description": "",
"processors": [
{
"script": {
"lang": "painless",
"source": "ctx.length=ctx.title.length()"
}
},
{
"set": {
"field": "split_title",
"value": "{{title}}"
}
},
{
"split": {
"field": "split_title",
"separator": " "
}
}
]
}

006_mapping_01 `speaker` and # `line_number` are unanalysed strings

PUT hamlet_1
{
"settings": {
"number_of_replicas": 0,
"number_of_shards": 1
},
"mappings": {
"properties": {
"speaker":{
"type":"text"
},
"line_number":{
"type":"keyword"
},
"text_entry":{
"type":"keyword"
}
}
}
}
speaker are unanalysed strings not text_entry

9.1对于最后三个pipeline的想法

先贴下代码

GET kibana_sample_data_flights/_search
{
  "size": 0,
  "aggs": {
    "flights_by_day": {
      "date_histogram": {
        "field": "timestamp",
        "calendar_interval": "day"
      },
      "aggs": {
        "destinations_by_day": {
          "terms": {
            "field": "DestCityName"
          }
        },
        "most_popular_destination_of_the_day": {
          "max_bucket": {
            "buckets_path": "destinations_by_day._count"
          }
        }
      }
    }
  }
}

GET kibana_sample_data_flights/_search
{
  "size": 0,
  "aggs": {
    "flights_by_day": {
      "date_histogram": {
        "field": "timestamp",
        "calendar_interval": "day"
      },
      "aggs": {
        "destinations_by_day": {
          "terms": {
            "field": "DestCityName"
          }
        },
        "most_popular_destination_of_the_day": {
          "max_bucket": {
            "buckets_path": "destinations_by_day._count"
          }
        }
      }
    },
    "day_with_most_flights": {
      "max_bucket": {
        "buckets_path": "flights_by_day._count"
      }
    }
  }
}

GET kibana_sample_data_flights/_search
{
  "size": 0,
  "aggs": {
    "flights_by_day": {
      "date_histogram": {
        "field": "timestamp",
        "calendar_interval": "day"
      },
      "aggs": {
        "destinations_by_day": {
          "terms": {
            "field": "DestCityName"
          }
        },
        "most_popular_destination_of_the_day": {
          "max_bucket": {
            "buckets_path": "destinations_by_day._count"
          }
        }
      }
    },
    "day_with_most_flights": {
      "max_bucket": {
        "buckets_path": "flights_by_day._count"
      }
    },
    "day_with_the_most_popular_destination_over_all_days": {
      "max_bucket": {
        "buckets_path": "flights_by_day>most_popular_destination_of_the_day"
      }
    }
  }
}

感觉他这个题目表达的不是很清楚，我觉得第一个应该是求每一天中DestCityName聚合后的最大值，第二个是求每一天聚合后document最多的一天，第三个应该是对第一个每天聚合出来的求一个最大值