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RainerHeintzmann avatar RainerHeintzmann commented on June 11, 2024

I looked a bit more at the trees and found a solution that sort of works:

balltree = BallTree(points)
maxdist = 10.0
idxs = inrange(balltree, points, maxdist, true)

and then you need to see if a point has more than one result.
But is this the best way of solving this problem?

from nearestneighbors.jl.

RainerHeintzmann avatar RainerHeintzmann commented on June 11, 2024

Maybe this is a good solution?:

"""
    nn_mutual(points)
    returns the mutual nearest neighbor distances and the index of the neares neighbor, both in matrix form.
"""
function nn_mutual(points)
    kdtree = KDTree(points)
    nns, nndist = knn(kdtree, points, 2)
    nns = [mynn[1] for mynn in nns]
    nndist = [myd[1] for myd in nndist]
    return nndist, nns
end

If so, should it maybe be part of the toolbox?

from nearestneighbors.jl.

BioTurboNick avatar BioTurboNick commented on June 11, 2024

You might be looking for the skip argument, which allows you to specify a function to decide which points in the tree to not match.

from nearestneighbors.jl.

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