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Computer-Network-A-Top-Down-Approach-Answer

Computer Network A Top-Down Approach Practice Answer

计算机网络 自顶向下方法 第六版 (中文版)

  • 课后题答案
  • 课文中实验答案
  • 编程作业和答案
  • Wireshark实验和答案

注:中文版与英文版不同的,一般按照中文版处理。

答案目录

第一章 计算机网络和因特网

第二章 应用层

第三章 运输层

第四章 网络层

第五章 链路层

第六章 无线网络和移动网络

第七章 多媒体网络

第八章 计算机网络中的安全

第九章 计算机网络中的安全

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computer-network-a-top-down-approach-answer's Issues

第二章习题答案可能有误

第二章习题的P7、P8答案应该有问题,RTT是往返时间 楼主可能以为RTT是一次请求或者一次响应的时间。
故P7的答案应该是:RTT0+RTT1+...+RTTn

补充第五章wireshark实验第15题

除了对应的ip地址不存在的情况外,还有一种可能是arp请求使用的是广播地址ff:ff:ff:ff:ff:ff,所以同网络下所有主机都能收到,而arp响应使用的是请求中的源地址,所以只有发出请求的主机可以收到

Wireshark实验:HTTP第17题答案有误

image
原答案
image
改正
image
可以看出两个图片GET请求的ip不同,说明两个图片在不同的服务器上,应该需要建立两个TCP连接和keep-alive持续连接没有关系。
需要进一步指出的是即使两个图片在同一个服务器上,keep-alive持续连接也分为非流水线连接(串行)和流水线连接(并行),无法通过keep-alive确定一台服务器上的资源是通过一个TCP连接串行还是并行传输的。

关于第一章复习题R12的一些问题

q:与分组交换网络相比,电路交换网络有哪些优点?在电路交换网络中,TDM比FDM有哪些优点
其中第一点:当发生拥塞等网络问题时,TDM中的数据丢失可能只会是一部分,而FDM中就可能是大部分或全部。

网络拥塞不是只有分组交换才会出现么,电路交换是直接端到端的连接为什么会发生拥塞

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