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char-rnn-tensorflow's Issues

关于中文输入的问题,loss为nan

请问,我训练模型的时候,英文输入没问题,中文输入多了个embwdding层,就会loss为nan,用tfdbg调试,发现第一次出现nan是Adam/update_embedding/sqrt,这应该是梯度爆炸了吗?模型里用了梯度截断了,还是不行,把梯度截断最大值设置到1.1都不行,请问大神知道什么原因吗

word_embedding

您好,看完您的代码之后,我有一些不太能够理解的地方,希望您能帮我解决一下。

  1. 为什么英文字母就用one-hot就行了,而中文就需要用embedding层。不同的英文单词之前也是应该有联系的吧?
  2. 为什么embedding层使用的是一个随机变量来查找出单词的vector。这样的话,每个词的向量表示,不就是随机的了吗?那这个词有什么具体的含义呢?

请问seq_output = tf.concat(self.lstm_outputs, 1)的用意是什么?

你好,想请教个问题。
我的运行下来,报错在
y_reshaped = tf.reshape(y_one_hot, self.logits.get_shape())

因为y_one_hot和self.logits的总元素数量不同,所以不能reshape。
我推算了一下:

  1. inputs的shape是(num_seqs, num_steps),经过tf.one_hot以后,lstm_inputs的shape变成(num_seqs, num_steps, num_classes)

  2. 我用的是cell是一层的lstm,lstm_inputs经过tf.nn.dynamic(cell, lstm_inputs, initial_state=self.initial_state)后,lstm_outputs的shape是(num_seqs, num_steps, lstm_size)

  3. lstm_outputs经过tf.concat(lstm_outputs, 1)以后,shape没有任何变化,再经过一些列运算后,shape就会有问题。

所以想问一下tf.concat(lstm_outputs, 1)这一步是做什么的?
感谢~

read_utils.py报错

\read_utils.py", line 26, in batch_generator
y[:, :-1], y[:, -1] = x[:, 1:], x[:, 0]
TypeError: 'NoneType' object does not support item assignment

RNN总是预测'\n'和'\r'

您好,在参考着您的思路自己搭建RNN时候,在训练时输出结果总是预测'\n'或者'\r',请问您当初在训练时有没有碰到这个问题(用的是周杰伦的歌词那个数据)。统计了一下,这两个字符出现的频次都大约在5000/70000远高于其他词的词频,请问有没有什么解决思路呢

在model.py里,sample子函数中,可以将c值赋给x[0,0]么?

这个代码的主要目的是预测下一个char。

 def sample(self, n_samples, prime, vocab_size):
        samples = [c for c in prime]
        sess = self.session
        new_state = sess.run(self.initial_state)
        preds = np.ones((vocab_size, ))  # for prime=[]
        for c in prime:
            x = np.zeros((1, 1))
            # 输入单个字符
            x[0, 0] = c
            feed = {self.inputs: x,
                    self.keep_prob: 1.,
                    self.initial_state: new_state}
            preds, new_state = sess.run([self.proba_prediction, self.final_state],
                                        feed_dict=feed)

        c = pick_top_n(preds, vocab_size)
        # 添加字符到samples中
        samples.append(c)

但是在这里,直接将c值赋给x[0,0]可以么?x开始初始化是int,但是c是str。我建立了个小程序跑这一段,

import numpy as np
prime = "beauty"
for c in prime:
    x = np.zeros((1,1))
    #x[0,0] = vocab_to_int[c]
    x[0,0] = c
    print("c",c)
    print("x",x)

报错说ValueError: could not convert string to float: 'b'。
请问您是怎么解决这个问题的?

预测时表现不好

你好,我的模型能够在训练集上拟合较好,但是在采样时却得不到这样通顺的句子,采样的方式也是采用了np.random.choice()方法,只训练了1000个epoch因为在当训练到几百次时即使用来学习率衰减loss也没有下降了。请问有关这个问题有什么解决思路吗

关于如何增量训练问题

你好!首先非常感谢你在百忙之中看我的issue,我现在的最大难题是电脑内存太小,训练语料(中文)太大,无法一次性加载,我希望能够分批增量训练,就是在原来模型基础上再次使用新文章进行补充训练,需要怎么改好那?好像字典字符映射也要修改?我多次尝试好像失败了。谢谢!

model.py中的对中文做embedding操作

embedding = tf.get_variable('embedding', [self.num_classes, self.embedding_size])
self.lstm_inputs = tf.nn.embedding_lookup(embedding, self.inputs)
这样就直接变成了中文的embedding表示吗?不是很明白这两句的意思

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