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algorithm_course's Issues

青蛙跳的时间复杂度？

我的思路使用逐步往前迭代，生成图的邻接矩阵的方法来做。
但是这样的话，在查看每一步前面所跳的步数 k 需要 O(n) 的时间。
我没有完全看懂你的代码，你的是把前面的节点存成邻接表了吗？这样的话，是不是最坏情况也需要 O(n) 呀？似乎不能常数次找到？

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