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Comments (2)

dljgs1 avatar dljgs1 commented on May 26, 2024

集合查询法(JS):
var singleNumber = function(nums) {
var dog = {};
nums.forEach((n)=>{dog[n]?delete dog[n]:dog[n]=true;})
return Object.keys(dog)
};

位运算法(python2)
class Solution(object):
def singleNumber(self, nums):
"""
:type nums: List[int]
:rtype: List[int]
"""
xor = reduce(lambda x,y:x^y,nums)
first_bit = [1<<i for i in range(32) if (1<<i)&xor][0]
res = reduce(lambda x,y:x^y,[n for n in nums if n&first_bit])
return [res,res^xor]

from blog.

nc0812 avatar nc0812 commented on May 26, 2024

new

from blog.

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