Comments (4)
很慢的递归解。。
var combine = function(n, k) {
var ret = [];
var fn = function(arr,deep){
if(deep==0) return ret.push(arr);
var max = arr[arr.length-1] || 0;
if(arr.length-max>n-k)return;
for(var i = max+1;i<=n;i++){
fn(arr.concat(i),deep-1);
}
}
fn([],k);
return ret;
};
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@dljgs1 为什么慢,看着还行啊
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可能是因为用递归的锅。可读性是好了,速度只超过了9%。。。
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回溯法,求子集问题
class Solution:
#代码借鉴的大佬的
def combine(self, n, k):
cans = {i+1 for i in range(n)}
def backtrack(temp, cans, k, res):
if len(temp) == k:
res.append(temp[:])
return res
if len(cans)+len(temp)<k:
return res
for x in cans:
temp.append(x)
cans_ = {y for y in cans if y>x} # 滤重
res = backtrack(temp, cans_, k, res)
temp.pop()
return res
res = backtrack([], cans, k, [])
return res
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