13章以后(14-19章)每章的readme没有更新。
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License: GNU General Public License v3.0
Hello,I found that in Exercise4.37 where you need to use C++-style type conversion to inplace C-style type convension for below expression
(d) pc = (char*) pv;
and you code is
pc = reinterpre_cast<char *>(pv);
My doubt is why not use a static_cast<char*> because in the content of static_cast there are words:
we can use a static_cast to retrieve a pointer value that was stored in a void* pointer
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