david-kariuki / ace-the-java-coding-interview Goto Github PK
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License: MIT License
Java project to learn advanced Data Structures and Algorithms
License: MIT License
Compute the Big O of an algorithm that involves nested loops, and increments the loop variables through multiplication.
public static void main(String[] args) {
int n = 10; // O(time complexity of the called function)
int sum = 0; //O(?)
double pie = 3.14; //O(?)
int var = 1; //O(?)
while(var < n) {
System.out.println("Pie: " + pie); //O(?)
for (int j = 0; j < var; j++) {
sum++; //O(?)
}
var *= 2; //O(?)
} //end of while loop
System.out.println("Sum: " + sum); //O(?)
}
Compute Big(O) of an algorithm that involves nested loops and the loop variables decrement.
public static void main(String[] args) {
int n = 10; // O(time complexity of the called function)
int sum = 0; //O(1)
double pie = 3.14; //O(1)
//O(?)
for (int var = n; var >= 1; var = var - 3) {
System.out.println("Pie: " + pie);
//O(?)
for (int j = n; j >= 0; j = j - 1) {
sum++;
}
} //end of outer for loop
System.out.println("Sum: " + sum);//O(1)
}
Compute the big O complexity of the code snippet given below.
public static void main(String[] args) {
int n = 10;
int sum = 0;
int j = 1;
double pie = 3.14;
for (int var = 0; var < n; var++) {
System.out.println("Pie: " + pie);
while(j < var) {
sum += 1;
j *= 2;
}
}
System.out.println("Sum: " + sum);
}
Compute the Big O complexity of the code snippet given below.
public static void main(String[] args) {
int n = 10;
int sum = 0;
double pie = 3.14;
for (int var = 0; var < n; var++) {
int j = 1;
System.out.println("Pie: " + pie);
while(j < var) {
sum += 1;
j *= 2;
}
} //end of for loop
System.out.println("Sum: " + sum);
}
A basic exercise based on the Big(O) of an algorithm that involves nested loops and the loop variables increment with multiplication.
public static void main(String[] args) {
int n = 10; // O(time complexity of the called function)
int sum = 0; //O(1)
double pie = 3.14; //O(1)
int var = 1; //O(?)
while(var < n) {
System.out.println("Pie: " + pie);
//O(?)
for (int j = 1; j < n; j = j + 2) {
sum++;
}
var *= 3;
} //end of while loop
System.out.println("Sum: " + sum); //O(1)
}
Compute the Big O complexity of the code snippet given below. It is better to solve it on a piece of paper, and then see if your answer matches the correct option!
public static void main(String[] args) {
int n = 10; //O(1)
int sum = 0; //O(1)
int j = 1; //O(1)
double pie = 3.14; //O(1)
//O(?)
for (int var = 1; var < n; var += 3) {
System.out.println("Pie: " + pie);
j = 1;
while (j < n) { //O(?)
sum += 1;
j *= 3;
}
}
System.out.println("Sum: " + sum); //O(1)
}
Compute the Big O complexity of an algorithm that involves nested loops where the loop variables increase with addition.
public static void main(String[] args) {
int n = 10;
int sum = 0;
double pie = 3.14;
for (int var = 0; var < n; var = var + 3) {
System.out.println("Pie: " + pie);
for (int j = 0; j < n; j = j + 2) {
sum++;
System.out.println("Sum = " + sum);
}
}
}
Problem Set 1 - 6
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