arcesilas / active-state Goto Github PK
View Code? Open in Web Editor NEWLaravel link active state helper based on URL, route or query string
License: MIT License
Laravel link active state helper based on URL, route or query string
License: MIT License
When I use the function if true would not it be to return the 'active_state' config?
I tried to install on version 6.6, but to no avail.
Hello, how are you?
I'm facing a problem, in my localhost the command {{ Active::ifRouteIs('site.cardapio', 'pizzas']) }}
is working normally, but when I uploaded the project to a shared server it does not seem to work to function.
I use 2 methods in the menu, the "ifRouteIn" which is working normally and the "ifRouteIs" that is not, however the 2 work normal in localhost.
Do you have any suggestions whatsoever?
Hello, how are you? I am trying to use the ifQueryHas method.
Laravel v5.5.48
active-state v2.1.0
I tried to follow this README example:
Check query string contains argument foo with value bar:
<a class="nav-link {{Active::ifQueryHas('videos.category', ['slug' => $category->slug])}}" href="{{ route('videos.category', $category->slug) }}">
Then returns me the following error:
my tag: <a class="nav-link {{Active::ifQueryHas('site.noticias.listar', ['pagina' => $noticias->currentPage()])}}" href="#">test</a>
I'm trying to use the package with a pagination that involves categories and search. I don't know if I'm doing it the right way. If so, could you inform me? thanks
I am using version 1.2 with Laravel 5.4
I have installed according to the instructions and added
'providers' => [
...
Arcesilas\ActiveState\ActiveStateServiceProvider::class,
]
to config/app.php
but I am receiving the error Class 'Arcesilas\ActiveState\ActiveStateServiceProvider' not found
Hello friend,
I'm using the package, however I realized that the "ifRouteIs" method is not working when used array.
Even though the route exists, validation is passed as if it does not exist.
I was even trying to make code changes, but I do not know how to cross-test in PHP.
Hello,
I started using your package...
the "Active::checkRoute()" method is working?
I did this test: {{ Active::checkRoute('user.index') }}
But returned:
ErrorException (E_ERROR) Call to undefined method Arcesilas\ActiveState\Active::checkRoute()
What can it be?
Hi,
I'm currently with Laravel 5.4, with "pyaesone17/active-state" v1.2.
Good update work.
Thank's
Doubt over class name configuration pass.
Would it be possible to pass the class name when calling the method? Example:
<li class="{{ Active::ifRouteIn('site.index', 'current') }}"><a href="{{ url('/') }}" title="Início"><div>Início</div></a></li>
Hi,
I just noticed that
https://test.localhost/notifications
and
https://test.localhost/notifications?all=1
return for
{{ active_url_is('notifications') }}
both the active
string.
May it be that query params are not part of the exact url check? I would like to differentiate between the path without and with query parameters. Is there something for that use case?
In the lib at line
Line 57 in 633d1ba
is()
method makes use of a string comparison with http://php.net/manual/en/function.rawurldecode.php at https://github.com/laravel/framework/blob/2906b572aa83ff46b8ad57093dd0e859c0ff783f/src/Illuminate/Http/Request.php#L148
And if I see that right, the url should be the whole thing.
Currently, Active::checkRouteIs()
accepts an array of routes, but the format of the array is a little complex, in my opinion, for an actual use in a view:
[
'some.route' => ['slug' => 'something'],
'route.test' => ['slug' => 'title']
]
@marcelogarbin do you think this usage is relevant?
Personnally, I think it's not really usable in a view and am considering to remove this functionnality. What do you think?
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