Comments (1)
题解
方法一
/**
* Definition for singly-linked list.
* function ListNode(val) {
* this.val = val;
* this.next = null;
* }
*/
/**
* @param {ListNode} l1
* @param {ListNode} l2
* @return {ListNode}
*/
var addTwoNumbers = function(l1, l2) {
let p1 = l1;
let p2 = l2;
let carry = 0;
const dummy = new ListNode();
let pointer = dummy;
while (p1 || p2 || carry) {
const num1 = p1 ? p1.val : 0;
const num2 = p2 ? p2.val : 0;
const sum = num1 + num2 + carry;
if (sum > 9) {
pointer.next = new ListNode(sum % 10);
carry = 1;
} else {
pointer.next = new ListNode(sum);
carry = 0;
}
if (p1) p1 = p1.next;
if (p2) p2 = p2.next;
pointer = pointer.next;
}
return dummy.next;
};
from leetcode.
Related Issues (20)
- 217.存在重复元素 HOT 1
- 4.寻找两个正序数组的中位数 HOT 1
- 8.字符串转换整数 (atoi) HOT 1
- 237.删除链表中的节点 HOT 1
- 238.除自身以外数组的乘积 HOT 1
- 46.全排列 HOT 1
- 160.相交链表 HOT 1
- 61.旋转链表 HOT 1
- 21.合并两个有序链表 HOT 1
- 92.反转链表 II HOT 1
- 206. 反转链表 HOT 1
- 146. LRU 缓存机制 HOT 1
- 94. 二叉树的中序遍历 HOT 1
- 235. 二叉搜索树的最近公共祖先 HOT 1
- 236. 二叉树的最近公共祖先 HOT 1
- 104. 二叉树的最大深度 HOT 1
- 111. 二叉树的最小深度 HOT 1
- 543. 二叉树的直径 HOT 1
- 124.二叉树中的最大路径和 HOT 1
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from leetcode.