[Bug] LaTeX 渲染异常 about chatgpt-next-web

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Title: [Bug] LaTeX rendering exception

Bug Description

How to reproduce: Enter the following content in the input box

In the C and C++ languages, the expression `(unsigned int)-1` is not Undefined Behavior (UB) for unsigned integer types such as `unsigned int`. This is because when you assign a value to an unsigned type, if the assigned value exceeds the range that the type can represent, the result will be the value modulo the maximum value that the unsigned type can represent plus one (that is, the value is within "surround" within the scope of this type).

In the case of `(unsigned int)-1`, since `-1` is first treated as a signed integer, then it is converted (or "cast") to the `unsigned int` type. In this case, `-1` is converted to an unsigned type by adding the largest value that can be represented by `unsigned int` plus one (that is, adding $2^{32}-1$, if `unsigned int` If it is 32 bits). The result is the maximum value that an `unsigned int` can represent, which is typically $2^{32}-1$ for a 32-bit `unsigned int`.

Therefore, this conversion is well-defined rather than undefined behavior. This behavior is explicit in the C and C++ standards, so you can rely on this behavior for your programming.

It should be rendered as:

In the C and C++ languages, the expression (unsigned int)-1 is not Undefined Behavior (UB) for unsigned integer types such as unsigned int. This is because when you assign a value to an unsigned type, if the assigned value exceeds the range that the type can represent, the result will be the value modulo the maximum value that the unsigned type can represent plus one (that is, the value is within "surround" within the scope of this type).

In the case of (unsigned int)-1, since -1 is first treated as a signed integer, then it is converted (or "cast") to the unsigned int type. In this case, -1 is converted to an unsigned type by adding the largest value that can be represented by unsigned int plus one (that is, adding $2^{32}-1$, if unsigned int If it is 32 bits). The result is the maximum value that an unsigned int can represent, which is typically $2^{32}-1$ for a 32-bit unsigned int.

Therefore, this conversion is well-defined rather than undefined behavior. This behavior is explicit in the C and C++ standards, so you can rely on this behavior for your programming.

It is actually rendered as:

Steps to Reproduce

How to reproduce: Enter the following content in the input box

In the C and C++ languages, the expression `(unsigned int)-1` is not Undefined Behavior (UB) for unsigned integer types such as `unsigned int`. This is because when you assign a value to an unsigned type, if the assigned value exceeds the range that the type can represent, the result will be the value modulo the maximum value that the unsigned type can represent plus one (that is, the value is within "surround" within the scope of this type).

In the case of `(unsigned int)-1`, since `-1` is first treated as a signed integer, then it is converted (or "cast") to the `unsigned int` type. In this case, `-1` is converted to an unsigned type by adding the largest value that can be represented by `unsigned int` plus one (that is, adding $2^{32}-1$, if `unsigned int` If it is 32 bits). The result is the maximum value that an `unsigned int` can represent, which is typically $2^{32}-1$ for a 32-bit `unsigned int`.

Therefore, this conversion is well-defined rather than undefined behavior. This behavior is explicit in the C and C++ standards, so you can rely on this behavior for your programming.

Expected Behavior

It should be rendered as:

In the C and C++ languages, the expression (unsigned int)-1 is not Undefined Behavior (UB) for unsigned integer types such as unsigned int. This is because when you assign a value to an unsigned type, if the assigned value exceeds the range that the type can represent, the result will be the value modulo the maximum value that the unsigned type can represent plus one (that is, the value is within "surround" within the scope of this type).

In the case of (unsigned int)-1, since -1 is first treated as a signed integer, then it is converted (or "cast") to the unsigned int type. In this case, -1 is converted to an unsigned type by adding the largest value that can be represented by unsigned int plus one (that is, adding $2^{32}-1$, if unsigned int If it is 32 bits). The result is the maximum value that an unsigned int can represent, which is typically $2^{32}-1$ for a 32-bit unsigned int.

Therefore, this conversion is well-defined rather than undefined behavior. This behavior is explicit in the C and C++ standards, so you can rely on this behavior for your programming.

Screenshots

Deployment Method

• Docker
• Vercel
• Server

Desktop OS

Windows 11

Desktop Browser

Microsoft Edge

Desktop Browser Version

123

Smartphone Device

No response

Smartphone OS

No response

Smartphone Browser

No response

Smartphone Browser Version

No response

Additional Logs

No response

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This bug related to this issue

• #3239