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cphyc avatar cphyc commented on June 27, 2024

Here's the whole code.

<!DOCTYPE html>
<html>
  <head lang="en">
    <meta charset="UTF-8">
    <title>Yjs test</title>
    <script src="https://ajax.googleapis.com/ajax/libs/jquery/1/jquery.min.js"></script>
    <script src="bower_components/webcomponentsjs/webcomponents.js"></script>
    <script src="bower_components/yjs/y.js"></script>
    <script src="bower_components/yjs/y-object.js"></script>
    <script src="bower_components/y-list/y-list.js"></script>
    <script src="bower_components/y-xml/y-xml.js"></script>
    <script src="bower_components/y-webrtc/y-webrtc.js"></script>
    <script src="config.js"></script>
  </head>
  <body>
    <p id="container">This is default.</p>
  </body>
  <script>
   var connector = new Y.WebRTC("test", {url: config.server});

   var y = new Y(connector);
   var p = document.getElementById("container");
   var yxml = new Y.Xml(p);

   y.val("test", yxml);

  </script>
</html>

from y-xml.

dmonad avatar dmonad commented on June 27, 2024

This is not a bug.

This is what happens: User 1 puts p on y("test"). User 2 joins the session and also puts its own version of p on y("test"). Therefore, the p element of user 1 is not shared anymore (because it was replaced by user 2. In the examples directory I show how you can ensure that there is only one version of p exists in the body.

Because this is a common usage of the xml type, I'll find a way to make this easier. I'll also include this in the documentation.

from y-xml.

cphyc avatar cphyc commented on June 27, 2024

Ok, thanks for the hint.

from y-xml.

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