Implement groupBy method for potentially infinite iterables about iterum

[xgbuils]

Working with potentially infinite iterables and groupBy implies that we are not able to know how many groups of iterable will be produced. For example, we can infer that this expression:

range(0, Infinity).groupBy(e => e % 3) 

just produces 3 groups ([0, 3, 6...], [1, 4, 7, ...] & [2, 5, 8, ...]), but we can not infer this for a generic function.

Then, I think that there are 2 approaches.

First approach:

const iterable = range(0, Infinity).groupBy(e => e % 3) 
const iterator = iterable[Symbol.iterator]()

const firstGroup = iterator.next().value // potentially [0, 3, 6, ...]
const secondGroup = iterator.next().value // potentially [1, 4, 7, ...]
const thirdGroup = iterator.next().value // potentially [2, 5, 8, ...]
const FourthGroup = iterator.next() // infinite loop because there are not another group and `range(0, Infinity)` never ends.

Second approach:

const iterable = range(0, Infinity).groupBy(e => e % 3) 
const iterator = iterable[Symbol.iterator]()

const firstGroup = iterator.next().value // potentially [0, 3, 6, ...]
const secondGroup = iterator.next().value // potentially [1, 4, 7, ...]
const thirdGroup = iterator.next().value // potentially [2, 5, 8, ...]
const FourthGroup = iterator.next() // returns lazy iterable
const Fifthgroup = iterator.next() // returns lazy iterable

// But then if we try to execute:
const it = FourthGroup[Symbol.iterator]()
it.next() // it produces an infinite loop because does not found any element that matches

Second approach is lazier than first approach. But first approach is more expected. For example, it look likes weird that happens this:

var iterable = Iterum([1, 6, 3, 4, 8, 3]).groupBy(e => e % 3)
/* following the second approach it returns [
    potentially [1, 4],
    potentially [6, 3, 3],
    potentially [8],
    potentially [],
    potentially [],
    potentially [],
    ...
] */
// then if we do:
[...iterable] // it produces an infinite loop and maybe it is more expectable returning [Iterum([1, 4]), Iterum([6, 3, 3]), Iterum([8])]

[xgbuils]

I implemented groupBy following the firs approach.