Comments (1)
The syntax here is a little ambiguous because braces are optional when using
$placeholder.
If you use ${placeholder} around the expression, everything will work correctly.
In this case:
var bar={ cat: ${foo($bar("dog"))} };
Original comment by [email protected]
on 12 Aug 2009 at 8:17
- Changed state: WontFix
from spitfire.
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from spitfire.