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happyflying-web avatar happyflying-web commented on July 21, 2024

原代码也是6.75°,但是根据程序英文介绍以及对应论文,都应该是5°才对,我看到您在这里也留了注释,不知道您是否了解?

// R = 6, 6.75 DEG: 当R=6时,每个方向的变化量
const float Node3D::dy[] = { 0,        -0.0415893,  0.0415893};
const float Node3D::dx[] = { 0.7068582,   0.705224,   0.705224};
const float Node3D::dt[] = { 0,         0.1178097,   -0.1178097};

您好可以发一下对应的论文名字吗,谢谢您

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LadissonLai avatar LadissonLai commented on July 21, 2024

这里是根据车辆运动学解算的,dx和dy是车辆自身坐标系。假设一次节点扩展,小车转向角变化为6.75度,对应弧度为0.1178097,根据车辆运动学模型,小车做圆周运动,圆周运动的半径为r=6 (constans::r),则弧长为 弧度*半径 = 0.1178097 * 6 = 0.7068582,正好是小车不转向的行驶距离。

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