Comments (2)
Add const { z } = require('zod')
or - for the billionth time - just use Ajv with the JSON schema instead of converting it
from json-schema-to-zod.
for the billionth time
@StefanTerdell the package name disinform everybody who's looking how to convert JSON to Zod. Programmatic example doesn't say anything about return type. What would somebody expect to get running the following code?
const schema = jsonSchemaToZod(myObject);
I would expect to return schema instead of a string. It would be fair to rename the project and update the example. Personally for me this confusion caused me to rethink completely what I was planning to do for 2 weeks and the fact that I noticed this issue just now costs me many hours of my time because I was naively relying on the part of the documentation that clearly describes programmatic use. Please, respect people who's going to use your thing.
from json-schema-to-zod.
Related Issues (20)
- allOf is not converted properly HOT 2
- Missing support for error messages from zod-to-json-schema
- Schema including `patternProperties` resulting in `z.any()` HOT 3
- Always giving z.any() in output HOT 1
- Getting unexpected zod schema as output HOT 1
- Could you pick prettier config if it exists in the project? HOT 1
- URL as JSON Schema Source HOT 1
- parseSchema requires second "Refs" argument? HOT 1
- Conversion of schema results in z.any() with CLI, but a correct schema on demo site HOT 1
- Supported JsonSchema Versions
- invalid default value codegen HOT 1
- Add an option to customize the parsing and output HOT 1
- additionalProperties: false breaks types HOT 2
- Error Messages are Missing in Zod Schema after conversion HOT 1
- TypeScript errors for 'Programmatic' example in README.md: is not assignable to parameter of type 'JSONSchema7' HOT 1
- Support strict option for zod object HOT 1
- add missing IP addresses string validations HOT 4
- Error ENAMETOOLONG when piping with json-refs HOT 4
- "not" patterns HOT 3
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from json-schema-to-zod.