Exif rotation and save about imagesharp

[JimBobSquarePants]

I’m not sure what you are expecting here. The image was rotated to match the exif orientation.

[bertasoft]

I'm expected that the rotated is like this

[JimBobSquarePants]

That's an incorrect assumption. AutoOrient update the orientation of the image to match the EXIF metadata properties and removes those properties from the metadata.

As you can see on your breakpoints. The input image has physical dimensions of 1536x2048 (portrait) but is displayed rotated 90degrees (landscape). Once processed the image pixels are 2048x1536 which matches the landscape display orientation of the input.

[bertasoft]

Ok, how can I have the rotated version of the image like my example?

Something that follow the exif infos and give me the jpg rotated, any c# code example?

Now i'm using something like this

private const int exifOrientationID = 0x112; //274

public static void ExifRotate(this Image img)
{
if (!img.PropertyIdList.Contains(exifOrientationID))
return;

var prop = img.GetPropertyItem(exifOrientationID);
int val = BitConverter.ToUInt16(prop.Value, 0);
var rot = RotateFlipType.RotateNoneFlipNone;

if (val == 3 || val == 4)
    rot = RotateFlipType.Rotate180FlipNone;
else if (val == 5 || val == 6)
    rot = RotateFlipType.Rotate90FlipNone;
else if (val == 7 || val == 8)
    rot = RotateFlipType.Rotate270FlipNone;

if (val == 2 || val == 4 || val == 5 || val == 7)
    rot |= RotateFlipType.RotateNoneFlipX;

if (rot != RotateFlipType.RotateNoneFlipNone)
{
    img.RotateFlip(rot);
    img.RemovePropertyItem(exifOrientationID);
}

}

Thanks for clarification,