MBTR about dscribe

[lauri-codes]

Hi @mansoure37!

The interface was changed in v2.0. You can see the new call syntax here. If you wish to compute different terms (k1, k2, k3), and combine them into a single vector, you would do something like this:

import numpy as np
from dscribe.descriptors import MBTR
from ase.build import bulk
import matplotlib.pyplot as mpl

# Define system
system = bulk('NaCl', crystalstructure='rocksalt', a=5.64)

# Setup and create
mbtr = MBTR(
    species=["Na", "Cl"],
    geometry={"function": "atomic_number"},
    grid={"min": 11, "max": 17, "n": 100, "sigma": 0.5},
    periodic=True,
    normalization="l2",
)
k1 = mbtr.create(system)
mbtr.geometry = {"function": "inverse_distance"}
mbtr.grid = {"min": 0, "max": 1, "n": 100, "sigma": 0.1}
mbtr.weighting = {"function": "exp", "scale": 0.5, "threshold": 1e-3}
k2 = mbtr.create(system)
mbtr.geometry = {"function": "cosine"}
mbtr.grid = {"min": 0, "max": 1, "n": 100, "sigma": 0.1}
mbtr.weighting = {"function": "exp", "scale": 0.5, "threshold": 1e-3}
k3 = mbtr.create(system)

# Combine along last axis
full = np.concatenate((k1, k2, k3), axis=-1)

# Plot
mpl.plot(full)
mpl.show()

[mansoure37]

thanks.
Another question is: I want to compare the Fingerprint of 2 compounds with the same elements but different space group number.Is it correct to make mbtr in the way that you said above for 2 compounds and compare their plotting or do you have another suggestion for making a Fingerprint?

[lauri-codes]

If you normalize the outputs to unit length (normalizer='l2' in the MBTR constructor), then you can in principle compare structures coming from different spacegroups and importantly also the same structure in different supercells sizes (read more here)