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Correct control_flow.cond usage about numpyro HOT 6 OPEN

tims457 avatar tims457 commented on July 18, 2024
Correct control_flow.cond usage

from numpyro.

Comments (6)

fehiepsi avatar fehiepsi commented on July 18, 2024 1

Yeah, it is a limitation of cond. JAX requires two branches to have the same pytree structure. I don't have a good solution for it. Depending on the algorithm, something like this (suitable for MCMC) might be required

def lazy_branch():
        amount_slept =  numpyro.sample("amount_slept", dist.Uniform(-100., 100.))
        numpyro.factor("amount_slept_factor", dist.Normal(loc=8+2*ignore_alarm, scale=1).log_prob(amount_slept))
        return amount_slept

Similar for the other branch

numpyro.factor("amount_slept_factor", 0.)

from numpyro.

fehiepsi avatar fehiepsi commented on July 18, 2024

I think you can move ignore_alarm outside of the lazy branch so that two branches have the same latent variables.

from numpyro.

tims457 avatar tims457 commented on July 18, 2024

That works in this particular case since both branches sample from a normal distribution but not in general. For example, what if one branch has a normal distribution and one has a uniform distribution? This throws the same error. However it is possible to do in Pyro

def sleep_model(data):
    feeling_lazy = numpyro.sample("feeling_lazy", dist.Bernoulli(probs=0.9))
    ignore_alarm = numpyro.sample("ignore_alarm", dist.Bernoulli(probs=0.8))

    
    def lazy_branch():
        amount_slept =  numpyro.sample("amount_slept", dist.Normal(loc=8+2*ignore_alarm, scale=1))
        return amount_slept
    
    def not_lazy_branch():
        # amount_slept numpyro.sample("amount_slept", dist.Normal(loc=6, scale=1)) # this works
        amount_slept = numpyro.sample("amount_slept", dist.Uniform(low=6., high=10.)) # this doesn't
        return amount_slept

    amount_slept = cond(feeling_lazy == 1, 
                        lambda x: lazy_branch(), 
                        lambda x: not_lazy_branch(),
                        data
    )
    return amount_slept

This works using Pyro.

def sleep_model():
    feeling_lazy = pyro.sample("feeling_lazy", dist.Bernoulli(0.9))
    
    if feeling_lazy:
        ignore_alarm = pyro.sample("ignore_alarm", dist.Bernoulli(0.8))
        amount_slept = pyro.sample("amount_slept",
                              dist.Normal(8 + 2 * ignore_alarm, 1))
    else:
        amount_slept = pyro.sample("amount_slept", dist.Uniform(1, 6))
    
    return amount_slept

from numpyro.

tims457 avatar tims457 commented on July 18, 2024

Unfortunate, but thank you.

from numpyro.

fehiepsi avatar fehiepsi commented on July 18, 2024

Just curious on what is the issue that you got?

from numpyro.

Related Issues (20)

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