Comments (3)
很不错的方案,但是给的四个点并不知道哪两个是对角线顶点,可能是AB,AC 或者 AD,需要遍历一下。由于哪个是左上并没有明确的定义,所以可以简单的以离原点最近的点作为 左上,之后再连线判断另外两个点是否在线的两侧来判断对角线,具体实现可以看:
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OK, 明白了,谢谢
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'''
判断四个点 左上左下,右上右下
左上的点为 最靠近左边的两个点中最靠近上面的点
如果能判断哪个点是左上,那么可以连接对角线,通过交点与四个点的大小关系判断位置,距离原点最近的不一定是左上
'''
if len(points) != 4:
print('wrong point num')
exit(0)
point_sort_left = sorted(points , key=lambda k: [k[0], k[1]])
lt, ld = sorted([point_sort_left[0], point_sort_left[1]], key=lambda k:[k[1], k[0]])
rt, rd = sorted([point_sort_left[2], point_sort_left[3]], key=lambda k:[k[1], k[0]])
display(lt, rt, rd, ld)
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