There was an Error about simplewebapi

[obaro]

Hi SameerKhan,

What API are you calling?

Send sample code, and I'll assist if I can

On Sat, Oct 15, 2016 at 2:36 PM, SameerKhan1406 [email protected]
wrote:

I am passing two values instead one and using my api url since it accepts
two parameter.

Just tell me how to api which i created i have my url and it accepts two
parameter and return response in Json which i want to print
{
Status=1
message"dewegow523yrinc" any random everytime i am calling
}

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[SameerKhan1406]

Thank you for asking. I am terrified since Saturday and i am beginner in android
Please resolve this
Find below detail for API :

URL : http://192.168.0.19/monika/slim_prj/public/code

Request Parameter (in POST)

• mac_address
• key

Response (in JSON) -

{
"status": 1,
"message": "qYNoQBImXRhOMety"
}

[SameerKhan1406]

Have you started working on how to do this thing?

[SameerKhan1406]

`This is my code``
package com.medmainfomatix.myapplication1;

import android.os.AsyncTask;
import android.os.Bundle;
import android.support.v7.app.AppCompatActivity;
import android.util.Log;
import android.view.View;
import android.widget.Button;
import android.widget.EditText;
import android.widget.ProgressBar;
import android.widget.TextView;

import java.io.BufferedReader;
import java.io.InputStreamReader;
import java.net.HttpURLConnection;
import java.net.URL;

public class MainActivity extends AppCompatActivity {

EditText emailText;
EditText emailText1;
TextView responseView;
ProgressBar progressBar;

static final String API_URL = "http://192.168.0.19/monika/slim_prj/public/code/";

@OverRide
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);

responseView = (TextView) findViewById(R.id.responseView);
emailText = (EditText) findViewById(R.id.emailText);
emailText1= (EditText) findViewById(R.id.emailText1);

progressBar = (ProgressBar) findViewById(R.id.progressBar);

Button queryButton = (Button) findViewById(R.id.queryButton);
queryButton.setOnClickListener(new View.OnClickListener() {
@OverRide
public void onClick(View v) {
new RetrieveFeedTask().execute();
}
});
}

class RetrieveFeedTask extends AsyncTask<Void, Void, String> {

private Exception exception;
String mac_address = emailText.getText().toString();
String key= emailText1.getText().toString();

protected void onPreExecute() {
progressBar.setVisibility(View.VISIBLE);
responseView.setText("");
}

protected String doInBackground(Void... urls) {

// Do some validation here

try {
URL url = new URL(API_URL + "mac_address=" + mac_address + "Key=" + key);
HttpURLConnection urlConnection = (HttpURLConnection) url.openConnection();
try {
BufferedReader bufferedReader = new BufferedReader(new InputStreamReader(urlConnection.getInputStream()));
StringBuilder stringBuilder = new StringBuilder();
String line;
while ((line = bufferedReader.readLine()) != null) {
stringBuilder.append(line).append("\n");
}
bufferedReader.close();
return stringBuilder.toString();
}
finally{
urlConnection.disconnect();
}
}
catch(Exception e) {
Log.e("ERROR", e.getMessage(), e);
return null;
}
}

protected void onPostExecute(String response) {
if(response == null) {
response = "THERE WAS AN ERROR";
}
progressBar.setVisibility(View.GONE);
Log.i("INFO", response);
responseView.setText(response);
// TODO: check this.exception
// TODO: do something with the feed

// try {
// JSONObject object = (JSONObject) new JSONTokener(response).nextValue();
// String requestID = object.getString("requestId");
// int likelihood = object.getInt("likelihood");
// JSONArray photos = object.getJSONArray("photos");
// .
// .
// .
// .
// } catch (JSONException e) {
// e.printStackTrace();
// }
}
}
}

[obaro]

How about you post on stackoverflow.
Your question and the solution would then be available to others who run into the same issue.

Let me know when you've made a post, so I'll answer it

[SameerKhan1406]

I already did that go to the link below :
http://stackoverflow.com/questions/40071964/android-i-need-to-call-web-api