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Comments (6)

telephon avatar telephon commented on June 12, 2024

A module doesn't know of the SynthDef args by default. But normally, you don't need to define a module if you just want to play a Synth defined in a SynthDef. Have you tried to just define the SynthDef and play it? You'll have remove the module or rename the SynthDef to make it work.

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ahihi avatar ahihi commented on June 12, 2024

i am intentionally defining modules in order to add some effects that i can use with any synth. so there is no way around having to specify in tidal every argument that should have a nonzero value?

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telephon avatar telephon commented on June 12, 2024

No, you should be able to just use the default values if you call the function dirtEvent.sendSynth(~instrument, ~argNames) (see the module ~dirt.addModule('sound',),

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telephon avatar telephon commented on June 12, 2024

(the ~argNames are generated automatically in DirtEvent from the ~instrument name).

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ahihi avatar ahihi commented on June 12, 2024

deleted my previous comment because i read too hastily and didn't realize ~argNames is an actual existing variable! 😅

ok, so all i needed to do was

(
~dirt.addModule('argtest', { |dirtEvent|
	dirtEvent.sendSynth('argtest' ++ ~dirt.numChannels, ~argNames);
}, { ~arg1.notNil || ~arg2.notNil });
)

that works, thank you!! :)

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telephon avatar telephon commented on June 12, 2024

Great!

a little more efficient (inlined "or"):

(
~dirt.addModule('argtest', { |dirtEvent|
	dirtEvent.sendSynth('argtest' ++ ~dirt.numChannels, ~argNames);
}, { ~arg1.notNil or: { ~arg2.notNil } });
)

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