How to fail a request? about fetch-intercept

[mlegenhausen]

Try to register two times. Each registration stands for a then(request, requestError) block. So when you raise an error in request you have a second then like then(request).then(null, requestError). Also try to vary the order of the rigistrations cause internally the registration will be executed in reverse order.

registerFetchIntercept({
  requestError: (error: any): Promise<void> => {
  }
});

registerFetchIntercept({
  request: async (url: string, options: any): Promise<[string, any]> => {
    //Check whether the url matches the regexp

    //check whether react native thinks we're offline
    const connectionInfo = await NetInfo.getConnectionInfo();
    if (connectionInfo.type === "NONE" || connectionInfo.type === "UNKNOWN") {
      throw new Error("Reachability Error - Device offline");
    }

    return [url, options];
  }
});

Maybe this helps.

[mlegenhausen]

Your current code does not return the promise. and you are using an async function. Your code should look something like this:

registerFetchIntercept({
  request: async (url: string, options: any): Promise<[string, any]> => {
    //Check whether the url matches the regexp

    //check whether react native thinks we're offline
    const connectionInfo = await NetInfo.getConnectionInfo();
    if (connectionInfo.type === "NONE" || connectionInfo.type === "UNKNOWN") {
      throw new Error("Reachability Error - Device offline");
    }

    return [url, options];
  },
  requestError: (error: any): Promise<void> => {
  }
})

Does this what you want?

[scott-mueller]

No, I need a way to make the code enter the 'requestError; block from within the 'request' block. So far just returning an error, or rejecting the promise doesn't cause that to happen