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lukepfister avatar lukepfister commented on July 22, 2024

I don't think it would break anything. If jitted there would be no performance change.

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bwohlberg avatar bwohlberg commented on July 22, 2024

I expect that the performance change would be small in any event, but are you really confident that the jit analysis would be able to identify a multiplication by a variable that happens to have been assigned as a unit matrix?

Independent of this, is it possible to re-arrange the representation a bit so that we can set W = 1.0 (i.e. a scalar) in the case of no weighting?

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lukepfister avatar lukepfister commented on July 22, 2024

iirc the default isn’t an IdentityMatrix, but rather the Identity LinOp— it’s eval is a no-op.

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lukepfister avatar lukepfister commented on July 22, 2024

cf

scico/scico/loss.py

Lines 214 to 215 in 4684909

if W is None:
self.W = linop.Identity(y.shape)

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tbalke avatar tbalke commented on July 22, 2024

Only concern would be that the diagonal is explicitly set to snp.ones:

super().__init__(diagonal=snp.ones(input_shape, dtype=input_dtype), **kwargs)

But can this be scalar 1.0?

Then it could be that the shape of W are different than the shape of W.diagonal. Not sure whether that is a problem.

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lukepfister avatar lukepfister commented on July 22, 2024

The shape of W and W.diagonal should be the same; we can't stop a user from doing something like W.diagonal = x where x.shape != W.shape, but that's just shooting themselves in the foot. The Diagonal class really treats the .diagonal attribute as a private thing, but Python doesn't have private attributes, so there you go.

As for identity: yes, it is true that Identity(shape).diagonal is a matrix of ones, but look at the eval:

scico/scico/linop/_linop.py

Lines 213 to 217 in 4684909

def _eval(self, x: Union[JaxArray, BlockArray]) -> Union[JaxArray, BlockArray]:
return x
def __rmatmul__(self, x: Union[JaxArray, BlockArray]) -> Union[JaxArray, BlockArray]:
return x

the .diagonal never gets used.

In earlier times, Identity did not inherit from Diagonal and this wasn't a problem

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tbalke avatar tbalke commented on July 22, 2024

In earlier times, Identity did not inherit from Diagonal and this wasn't a problem

What then is the reasoning to inherit from diagonal? Seems like in other contexts (other than the issue at hand) it may also be wasteful to store ones.

In other words, if SquaredL2Loss inherits from WeightedSquaredL2Loss and it is slightly inefficient, that is not exactly because of the inheritance but because the identity operator has some inefficiency?

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tbalke avatar tbalke commented on July 22, 2024

Also, this means that I(x) is very different than I.diagonal * x, if I is the Identity operator.

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lukepfister avatar lukepfister commented on July 22, 2024

I suppose you could relax W.diagonal to be something that broadcasts up to input_shape.

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