Not able to print the even the basic packet information from the saved file about pyshark

[bbayles]

@malli02422, change your cap=pyshark.FileCapture('D:\mallik.cap') line to cap=pyshark.FileCapture(r'D:\mallik.cap')?

[bbayles]

Discussion continued in #60; closing this.

[malli02422]

Hi
still I am Getting the same thing .
import pyshark

cap=pyshark.FileCapture(r'D:\mallik.cap')
print cap[0]

C:\Python27\python.exe "D:/Trailproject/string conversion.py"
Traceback (most recent call last):
File "D:/Trailproject/string conversion.py", line 5, in
print cap[0]
File "C:\Python27\lib\site-packages\pyshark\capture\file_capture.py", line 58, in getitem
self.next()
File "C:\Python27\lib\site-packages\pyshark\capture\file_capture.py", line 48, in next
packet = self._packet_generator.send(None)
File "C:\Python27\lib\site-packages\pyshark\capture\capture.py", line 159, in _packets_from_tshark_sync
tshark_process = existing_process or self.eventloop.run_until_complete(self._get_tshark_process())
File "C:\Python27\lib\site-packages\trollius\base_events.py", line 300, in run_until_complete
return future.result()
File "C:\Python27\lib\site-packages\trollius\futures.py", line 287, in result
raise self._exception
WindowsError: [Error 123] The filename, directory name, or volume label syntax is incorrect

Process finished with exit code 1

[goretkin]

Can you run the command

f = open(r'D:\mallik.cap')

?

[malli02422]

I have run the command and found the following out put.

f=open(r'D:\mallik.cap')
print f

C:\Python27\python.exe "D:/Trailproject/string conversion.py"
<open file 'D:\mallik.cap', mode 'r' at 0x01CCA230>

Process finished with exit code 0

On Fri, Feb 20, 2015 at 11:00 PM, Gustavo Goretkin <[email protected]

wrote:

Can you run the command

f = open(r'D:\mallik.cap')

?

—
Reply to this email directly or view it on GitHub
#52 (comment).

Best Regard
Mallikarjuna Reddy Thathekalva

[malli02422]

I have tried this
r=file(r'D:\mallik.pcap')
while True:
line=r.readline()
if (len(line)==0):
break
line=line.rstrip('\n')
print line
r.close()

And I got following output

C:\Python27\python.exe D:/Trailproject/packetCapture.py

� M<+

Process finished with exit code 0

I am not able to use it with windows and I have verified the following code as well
import pyshark
capture=pyshark.FileCapture('D:\mallik.pcap')
print capture.len()

C:\Python27\python.exe D:/Trailproject/packetCapture.py
0

Process finished with exit code 0

The array length is Zero
will only work with Linux ?? is there is any way to use it with windows??

[bbayles]

Using \ characters in paths is going to cause a problem - use r'D:\mallik.pcap' or 'D:/mallik.pcap'. See here.

I think that a more appropriate venue for these questions is Stack Overflow. If you make a post there and send me the link I will help you there.

[malli02422]

Hi ,
Unfortunately This doesn't work out .
Please find the code that I have edited

import pyshark
capture=pyshark.FileCapture(r"D:\mallik.pcap")
print capture.len()

C:\Python27\python.exe D:/Trailproject/packetCapture.py
0

Process finished with exit code 0

Find the attached pcap file . I can't able o execute the very basic command
as well. I don't how I can use this library

On Mon, Mar 9, 2015 at 7:52 PM, Bo Bayles [email protected] wrote:

Using \ characters in paths is going to cause a problem - use
r'D:\mallik.pcap' or 'D:/mallik.pcap'. See here
https://pythonconquerstheuniverse.wordpress.com/2008/06/04/gotcha-%E2%80%94-backslashes-in-windows-filenames/
.

I think that a more appropriate venue for these questions is Stack
Overflow. If you make a post there and send me the link I will help you
there.

—
Reply to this email directly or view it on GitHub
#52 (comment).

Best Regard
Mallikarjuna Reddy Thathekalva