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Richard004 avatar Richard004 commented on August 15, 2024

Hi, this is my guess. It would definitely work.
But at a certain moment, the depth of the graph can be so large that one risks stack overflow.
It feels like a tradeoff between simplicity and robustness of the example. But I am not sure if that was the real concern.

My concern was that we are creating the order with each call of the back propagation, while it typically remains constant over the whole optimization process. So the order could easily be cached somewhere. But that is just performance problem, I undestand that this was supposed to be explanation of the principle.

And it is a great one! ❤

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deermichel avatar deermichel commented on August 15, 2024

Great question, I was wondering the same 👍🏽

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t0lya avatar t0lya commented on August 15, 2024

Hi, this is my guess. It would definitely work. But at a certain moment, the depth of the graph can be so large that one risks stack overflow. It feels like a tradeoff between simplicity and robustness of the example. But I am not sure if that was the real concern.

My concern was that we are creating the order with each call of the back propagation, while it typically remains constant over the whole optimization process. So the order could easily be cached somewhere. But that is just performance problem, I undestand that this was supposed to be explanation of the principle.

And it is a great one! ❤

Topological sort in micrograd is implemented using recursion, so the stack overflow concern is same as when calling backward() recursively

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t0lya avatar t0lya commented on August 15, 2024

The graph is not necessarily a tree, it can have diamonds, see tinygrad/tinygrad#165 (comment)

Checking visited nodes during topological sort prevents repeat backward calls on same node

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