display CU_PARAM_TR_DEFAULT in checkdrv and what is it? about cudart.jl

[Roger-luo]

Sorry, I need to re-open this, as this error stops the program again.

I used following code to test if it's the server's or bsub's problem, but CUDA C++ works fine with both bsub and manually run:

// device code
#include <cuda.h>
#include <stdio.h>

typedef struct
{
    float x;
    float y;
}complex;


int main()
{
    CUdevice device;
    CUcontext context;
    CUmodule module;
    CUfunction kernel;
    CUdeviceptr dptr[2];

    cuInit(0);

    cuDeviceGet(&device, 0);
    cuCtxCreate(&context,CU_CTX_SCHED_AUTO,device);
    int t = cuModuleLoad(&module,"diagexp.ptx");
    cuModuleGetFunction(&kernel,module,"diagexp_cf");
    printf("%d",t);

    #define n_thread 3
    size_t size = n_thread*sizeof(complex);
    cuMemAlloc(&dptr[0],size);
    cuMemAlloc(&dptr[1],size);

    complex *A = (complex *)malloc(3*sizeof(complex));
    complex *C = (complex *)malloc(3*sizeof(complex));
    for(int i=0;i<3;i++)
    {
        A[i].x = i;
        A[i].y = 0;
        C[i].x = 0;
        C[i].y = 0;
    }

    cuMemcpyHtoD(dptr[0],A,size);
    cuMemcpyHtoD(dptr[1],C,size);

    int len = 3;
    void *params[] = {&dptr[0],&dptr[1],&len};
    cuLaunchKernel(kernel,1,1,1,3,1,1,0,NULL,params,0);
    cuCtxSynchronize();

    cuMemcpyDtoH(C,dptr[1],size);
    for(int i=0;i<3;i++)
        printf("%f\t%f\n",C[i].x,C[i].y);

    cuMemFree(dptr[0]);
    cuMemFree(dptr[1]);
    cuModuleUnload(module);
    cuCtxDestroy(context);
    return 0;
}

This works fine both with bsub and laptop.

But the -1 error still occurs when I submit the Julia code to the server. My program is here AdiaComput