Comments (1)
You should be able to follow the "Basic Usage" from the README, just without the db.create_all()
statement. Create your SQLA models identical to what's in your DB and you should be able to query against it the same way you would if you were using it to create a new DB.
from sqla-wrapper.
Related Issues (18)
- Inheritance does not work properly HOT 3
- db.init_app() doesnt apply app's configuration HOT 1
- Add association_proxy to sqlalchemy_wrapper.SQLAlchemy HOT 1
- I want to use custom metaclass HOT 1
- Unit Test example with wrapper
- Add a query attribute attached that can be used to query the model as in Flask-SQLAlchemy HOT 2
- User.query AttributeError HOT 1
- Wrong syntax in quickstart doc
- Two Pypi (pip) packages HOT 2
- default extend_existing to True HOT 1
- Did `PatchedScopedSession` function's argument naming correct?
- Add `py.typed` file to indicate the library is typed
- Does it support Asynchronous I/O? HOT 1
- Incompatible with just-released SQLAlchemy 2.0 HOT 2
- UnicodeEncodeError: 'ascii' codec can't encode character u'\u2019' in position 63: ordinal not in range(128) HOT 2
- Flask debug toolbar doesnt show queries(shows unavailable) HOT 2
- How to use custom declarative_base model? HOT 2
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from sqla-wrapper.