How to return the URL of an uploaded document about python-upload2sharepoint

[iamlu-coding]

Let me do some testing and I will get back to you. Thanks Lu From: rickmedlin ***@***.***> Sent: Friday, May 27, 2022 6:49 PM To: iamlu-coding/python-upload2sharepoint ***@***.***> Cc: Subscribed ***@***.***> Subject: [iamlu-coding/python-upload2sharepoint] How to return the URL of an uploaded document (Issue #2) With office365.runtime, I did it as shown below. How would you suggest doing it with SharePlum? # Get authorization from the site url. ctx = ClientContext(siteurl, ctx_auth) with open(localpath, 'rb') as content_file: file_content = content_file.read() dir, name = os.path.split(remotepath) file = ctx.web.get_folder_by_server_relative_url(dir).upload_file(name, file_content).execute_query() sourcedoc = '{' + file.properties['UniqueId'] + '}' fullurl = siteurl + '_layouts/15/Doc.aspx?sourcedoc=' + urllib.parse.quote(sourcedoc) — Reply to this email directly, view it on GitHub<#2>, or unsubscribe<https://github.com/notifications/unsubscribe-auth/ARPONWJMFC52ARENY7TPZ4TVMFURDANCNFSM5XFZYSJQ>. You are receiving this because you are subscribed to this thread.Message ID: ***@***.******@***.***>>

[rickmedlin]

I looked at the documentation for SharePlum and came up with this:

from shareplum import Site
from shareplum import Office365
from shareplum.site import Version

authcookie = Office365('https://mysite.sharepoint.com', username='user', password='password').GetCookies()
site = Site('https://mysite.sharepoint.com/sites/Test/', version=Version.v2016, authcookie=authcookie)
folder = site.Folder('Shared Documents/2022')

print(folder.files[0]['LinkingUrl'])

This prints out the 'LinkingUrl' attribute, which is exactly what I need to create a link in the PHP page. Now, the question is how to return that value after the upload.