Comments (3)
hfutrell
commented on August 19, 2024
1
@typoland the BezierCurve type doesn't have a cgPath property but Path does, so you can do Path(curve: ...).cgPath instead.
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hfutrell
commented on August 19, 2024
Hello. Thanks for the example. It looks like this is a problem in BezierCurve.outline(distance:). I'll fix that.
As a workaround I'd suggest checking if all the points in the curve are equal and if so doing some special handling like using a circular path with the proper radius, for example.
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typoland
commented on August 19, 2024
Hello! For now i just tested if points are the same and if so, moved one of them by 0.001. :)
Btw. I could not found some .cgPath() function to convert BezierCurve to CGPath. Is it exist?
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Related Issues (20)
- boundingBox vs boundingBoxOfPath follows opposite convention as CoreGraphics
- Hard to work with ends of simple, unclosed bezier path HOT 2
- Path and PathComponent hash and hashValue is simply memory address HOT 1
- Unknown references to BezierKit.min(...) and BezierKit.max(...) HOT 3
- Path.offset(distance:) hits assertion failure when called on a Path where all points are equal HOT 1
- Union of 2 overlapping paths returns an empty path HOT 4
- `union` with nonzero winding rule HOT 9
- Path.crossingRemoved() produces wrong result HOT 11
- simplifying a curve? HOT 2
- `offset` seems to treat straight & curved segments differently HOT 3
- feature request: permit separate x and y inputs for scale, outline, reduce HOT 8
- this contour crashes `crossingsRemoved` HOT 9
- `crossingsRemoved` makes these two contours disappear HOT 12
- how to quiet the SwiftLint warning? HOT 2
- `crossingsRemoved` gets confused by coincident points HOT 3
- droots can have low precision in some cases, which could affect Path.contains(_ point:)
- Newton iteration may fail to converge, producing wrong results in curve.project()
- Impossible to make closed PathComponent HOT 19
- Proposal: Use Sylvester Matrix for finding the intersection of cubic beziers HOT 1
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