Conditionals about python

[lionpower7]

#For Python.

mystery_int_1=int()
mystery_int_2=int()

mystery_int_1=input("Enter a Number:")
mystery_int_2=input("Enter another Number:")

if mystery_int_1% mystery_int_2 == 0 or mystery_int_2% mystery_int_1 == 0 :
print("Factors!")
else:
print(" ")`

[lionpower7]

I did It!!
Had to go back to school for this one, But Thank God I Did It.

[coded92]

Yeah...so correct

[lionpower7]

Problem Solved

Mystery_String = raw_input('Enter a String:'))

One = 'z'
ZZ = 'zz'
Sleepy = 'zzz'

if Sleepy in Mystery_String:
ZZ == False
One == False
print("Im Sleepy...")
elif ZZ in Mystery_String:
One == False
print("I Love ZZ Top!")
elif One in Mystery_String:
print("One is the loneliest number.")
elif One not in Mystery_String:
print("Who need's z anyway?"

[lionpower7]

Hey, Can I Try With Python?

I think i can do it (I am kind of new to programming but looks pretty easy...)

[coded92]

check this out

mystery_string = "zizazzle"

You may modify the lines of code above, but don't move them! When you Submit your code, we'll change these lines to assign different values to the variables.

The variable above creates a string. Add some code below that will print based on the maximum number of consecutive z's in the string:

• If z appears three or more times in a row, print "I'm sleepy..."
• If z appears two times in a row, print "I love ZZ Top!"
• If z appears once, print "One is the loneliest number."
• If z does not appear, print "Who needs z anyway?"

The message you print should correspond to the most consecutive z's: in the original value of mystery_string, for example, you'd print "I love ZZ Top!" because there are two consecutive z's, even though there are also some individual z's.

Ignore upper-case z's -- only look for lower-case z's.

Hint: Remember the 'in' operator! It returns true if the first string is found within the second string. For example, "bog" in "boggle" would return True, but "bog" in "artemis" would return False.

Comment your code

[lionpower7]

Ok i Will try.

…

On Mar 8, 2018 6:46 PM, "coded92" ***@***.***> wrote: check this out mystery_string = "zizazzle" You may modify the lines of code above, but don't move them! When you Submit your code, we'll change these lines to assign different values to the variables. The variable above creates a string. Add some code below that will print based on the maximum number of consecutive z's in the string: - If z appears three or more times in a row, print "I'm sleepy..." - If z appears two times in a row, print "I love ZZ Top!" - If z appears once, print "One is the loneliest number." - If z does not appear, print "Who needs z anyway?" The message you print should correspond to the most consecutive z's: in the original value of mystery_string, for example, you'd print "I love ZZ Top!" because there are two consecutive z's, even though there are also some individual z's. Ignore upper-case z's -- only look for lower-case z's. Hint: Remember the 'in' operator! It returns true if the first string is found within the second string. For example, "bog" in "boggle" would return True, but "bog" in "artemis" would return False. Comment your code — You are receiving this because you commented. Reply to this email directly, view it on GitHub <#303 (comment)>, or mute the thread <https://github.com/notifications/unsubscribe-auth/AjEpE0oi2uSoBOJnzHGvXosL4FyP1h7iks5tccLDgaJpZM4SSiuB> .

[coded92]

Can you do this

hour = 11
minute = 45

#You may modify the lines of code above, but don't move them!
#When you Submit your code, we'll change these lines to
#assign different values to the variables.

#Around Georgia Tech, there are plenty of places to get a
#late night bite to eat. However, they have different hours,
#so when choosing where to go, you have to think about who's
#still open!

#Imagine you're choosing between the following restaurants:

- Barrelhouse: Closes at 11:00PM

- Taco Bell: Closes at 2:00AM

- Cookout: Closes at 3:00AM

- Waffle House: Never closes. Ever.

#Assume that this list is also a priority list: if Barrelhouse
#is open, you choose Barrelhouse. If not, you choose Taco Bell
#if it's open. If not, you choose Cookout if it's open. If
#not, you choose Waffle House.

#However, there are two wrinkles:

- We're using 12-hour time.

- hour will always represent a time from 10PM to 5AM.

#That means that if hour is 10 or 11, it's PM; if hour is
#12, 1, 2, 3, 4, or 5, it's AM. This will make your reasoning
#a little more complex. You may assume that all four
#restaurants open later than 6AM, though, so you don't have
#to worry about opening time, just closing time.

#Add some code below that will print what restaurant you'll
#go to based on the current values of hour and minute.

#Add your code here!

[lionpower7]

x = [10,11,12,1,2,3,4,5]

y = [0, 1, 2, 3, 4, 5, 6, 7, 8, 9,10,11,12,13,14,15,16,17,18,19,20,
21, 22, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40,
41, 42, 43, 44, 45, 46, 47, 48, 49, 50, 51, 52, 53, 54, 55, 56, 57, 58, 59,]

hour = int()
minute = int()

hour = input("Enter the Hour:")
minute = input("Enter the Minute:")

if hour == x[0]:
print("BarrelHouse !!!")
elif hour == x[1]:
print("Taco Bell !!!")
elif hour == x[2]:
print("Taco Bell !!!")
elif hour == x[3]:
print("Taco Bell !!!")
elif hour == x[4]:
print("CookOut !!!")
elif hour == x[5]:
print("Waffle House !!!")

if hour not in x:
print("Enter an Hour Between 10 Pm & 5 Am!")
elif minute not in y:
raise ValueError
print("An Hour Only Has 60 Minutes!")

[lionpower7]

^Instead of [01,02,03,04,05,06,07,08,09], Just Enter [1,2,3,4,5,6,7,8,9]^

[lionpower7]

I did it already, check out conditionals 303 your issue.

…

On Mar 13, 2018 7:43 PM, "coded92" ***@***.***> wrote: Can you do this hour = 11 minute = 45 #You may modify the lines of code above, but don't move them! #When you Submit your code, we'll change these lines to #assign different values to the variables. #Around Georgia Tech, there are plenty of places to get a #late night bite to eat. However, they have different hours, #so when choosing where to go, you have to think about who's #still open! #Imagine you're choosing between the following restaurants: - Barrelhouse: Closes at 11:00PM - Taco Bell: Closes at 2:00AM - Cookout: Closes at 3:00AM - Waffle House: Never closes. Ever. #Assume that this list is also a priority list: if Barrelhouse #is open, you choose Barrelhouse. If not, you choose Taco Bell #if it's open. If not, you choose Cookout if it's open. If #not, you choose Waffle House. #However, there are two wrinkles: - We're using 12-hour time. - hour will always represent a time from 10PM to 5AM. #That means that if hour is 10 or 11, it's PM; if hour is #12 <#12>, 1, 2, 3, 4, or 5, it's AM. This will make your reasoning #a little more complex. You may assume that all four #restaurants open later than 6AM, though, so you don't have #to worry about opening time, just closing time. #Add some code below that will print what restaurant you'll #go to based on the current values of hour and minute. #Add your code here! — You are receiving this because you commented. Reply to this email directly, view it on GitHub <#303 (comment)>, or mute the thread <https://github.com/notifications/unsubscribe-auth/AjEpEwCKAPulsG1ReFNyVszD-ebTo-ocks5teFm4gaJpZM4SSiuB> .

[Naman-Garg-06]

Mystery_String = str(input('Enter a String:'))

One = 'z'
ZZ = 'zz'
Sleepy = 'zzz'

if Sleepy in Mystery_String:
ZZ == False
One == False
print("Im Sleepy...")
elif ZZ in Mystery_String:
One == False
print("I Love ZZ Top!")
elif One in Mystery_String:
print("One is the loneliest number.")
elif One not in Mystery_String:
print("Who need's z anyway?"

In this solution, there is no need to explicitly convert the input to string as input is taken as a string only.
Also why have you denoted ZZ and One as False in the conditional part? I think thw code will rum without that also.

[lionpower7]

Im not sure if it would have worked with zz == False or One == False, i tried so many ways and times but this is the only thing that worked for me.

…

On Mar 23, 2018 11:25 AM, "Naman Kumar Garg" ***@***.***> wrote: Mystery_String = str(input('Enter a String:')) One = 'z' ZZ = 'zz' Sleepy = 'zzz' if Sleepy in Mystery_String: ZZ == False One == False print("Im Sleepy...") elif ZZ in Mystery_String: One == False print("I Love ZZ Top!") elif One in Mystery_String: print("One is the loneliest number.") elif One not in Mystery_String: print("Who need's z anyway?" In this solution, there is no need to explicitly convert the input to string as input is taken as a string only. Also why have you denoted ZZ and One as False in the conditional part? I think thw code will rum without that also. — You are receiving this because you commented. Reply to this email directly, view it on GitHub <#303 (comment)>, or mute the thread <https://github.com/notifications/unsubscribe-auth/AjEpEzKzgfsu0CWhz8TWfgYuLvlDVFYvks5thRPwgaJpZM4SSiuB> .

[kolyamf]

zzz = "zzz"
zz = "zz"
z = "z"
if zzz in mystery_string:
zz == False
z == False
print("I'm sleepy...")
elif zz in mystery_string:
z == False
zzz == False
print("I love ZZ Top!")
elif z in mystery_string:
zzz == False
zz == False
print("One is the loneliest number.")
else:
print("Who needs z anyway?")

[Geethikagb]

check this out

mystery_string = "zizazzle"

You may modify the lines of code above, but don't move them! When you Submit your code, we'll change these lines to assign different values to the variables.

The variable above creates a string. Add some code below that will print based on the maximum number of consecutive z's in the string:

• If z appears three or more times in a row, print "I'm sleepy..."
• If z appears two times in a row, print "I love ZZ Top!"
• If z appears once, print "One is the loneliest number."
• If z does not appear, print "Who needs z anyway?"

The message you print should correspond to the most consecutive z's: in the original value of mystery_string, for example, you'd print "I love ZZ Top!" because there are two consecutive z's, even though there are also some individual z's.

Ignore upper-case z's -- only look for lower-case z's.

Hint: Remember the 'in' operator! It returns true if the first string is found within the second string. For example, "bog" in "boggle" would return True, but "bog" in "artemis" would return False.

Comment your code

Python 3

mystery_string = input("Enter input string : ")

if 'zzz' in mystery_string:
print("i'm sleepy...")
elif 'zz' in mystery_string:
print("i love ZZ top!")
elif 'z' in mystery_string:
print("One is the loneliest number")
else:
print("who needs z anyway")

[RonaldST1996]

Hi.
#$%!what#$%!

[NitkarshChourasia]

WORST / BAD QUALITY PROGRAMS WRITTEN ABOVE.

OP / @geekcomputers PLEASE CLOSE THIS, ASAP.