Comments (7)
你好,这是什么意思呢?
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如果这样atomic.AddUint64(&,1),我会报错,建议改成:atomic.AddUint64(&,uint64(1))
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字面值不是应该自动转换类型么?
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@liujarrett 具体报错信息能否提供
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atomic.AddUint64(),要求传入uint64,如果直接写1,应该是int,所以会出错。
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@liujarrett 你好,你可能电脑上没有Go开发环境吧?可以尝试在http://play.golang.org
上做一些小实验的。
比如基于你的假设,我做了以下实验,虽然这算是编程基础,但是不是所有人一开始都懂,可以理解。
package main
import "fmt"
func main() {
var count uint64
AddUint64(&count, 1)
AddUint64(&count, 2)
fmt.Printf("count = %d", count)
}
func AddUint64(target *uint64, v uint64) {
*target += v
}
你可以在这个网址:http://play.golang.org/p/V1t7oDPAMz 上直接运行这一段代码,看一下运行结果 :)
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@liujarrett 其实字面值使用之前是没有类型的,字面值1在函数参数为uint64的情况下会自动转换为uint64的,当然无法转换会报错,具体报什么错没测试,golang对于字面值从使用方便方面考虑,还是有一套自动转换的机制的.当然,紧紧是字面值.
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