How to implement git commit command about jproc

[fleipold]

This means that the git command returned a non zero exit code (1). Interestingly there is no error output (this would normally be included in the exception.
Unfortunately standard out is not captured in the exception. You can suppress the exception with:

result = new ProcBuilder("git")
            .withArgs("commit","-m").withArg(""+(char)34+"1st commit"+(char)34+"")
            .withExpectedExitStatuses(0, 1)
            .run();

If you then print the output like so:

System.out.println(result.getOutputString());
//now bail
if (result.getExitValue()!=0)
  throw new RuntimeException("Failed to run git");

You might see what is going wrong.

Also, you don't need to add the quotation marks to the argument. they normally tell bash that your message is a single argument, i.e. they are stripped off when the arguments are passed to the process.

[Rupangkan]

@fleipold Thank you, I found out the flaw in my code. Your suggestion was beneficial.

[fleipold]

@Rupangkan I am glad you figured it out. Thank you for this bug report. I have improved the exception message, so it now includes standard out from the failed command (available in the latest release 2.5.1), here an example:

Exception in thread "main" org.buildobjects.process.ExternalProcessFailureException: External process `git` terminated with unexpected exit status 1 after 39ms:
  $ git commit -m '1st commit'
  STDOUT: On branch master
  STDOUT:
  STDOUT: Initial commit
  STDOUT:
  STDOUT: nothing to commit (create/copy files and use "git add" to track)