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alice-cool avatar alice-cool commented on August 16, 2024

第8页,如果同构图是指图中的节点类型和关系类型都仅有一种。那么这种图就不会存在节点分类。因为节点只有一种类型。

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FighterLYL avatar FighterLYL commented on August 16, 2024

作者您好,我感觉第五页K阶子图定义有些问题。这里面写的E‘={eij|任意 vj,d(vi,vj)<=k}
这里面如果eij图中根本不存在这条边,但是存在这个路径所以说这可能会有些问题。所以我认为E‘={elm|任意 vj,d(vi,vj)<=k,elm属于Pij}
希望得到您的回复。目前正在认真阅读图卷积知识。

你理解的对, 严格来说这个定义需要保证e_{ij}在边的集合中

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FighterLYL avatar FighterLYL commented on August 16, 2024

第8页,如果同构图是指图中的节点类型和关系类型都仅有一种。那么这种图就不会存在节点分类。因为节点只有一种类型。

这个地方你混淆了节点类型与标记, 比如说由论文引用关系构成的图中, 节点类型只有论文, 关系只有引用, 因此是一个同构图, 但可以进行论文领域分类的任务

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alice-cool avatar alice-cool commented on August 16, 2024

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