Add a way to get all nodes in a radius about fast_paths

[easbar]

Starting from some node p you want to find all nodes q such that the weight of the shortest path p->q is less than some threshold ?

[Eh2406]

Yes. That is what I had in mind.

[Eh2406]

Now that I think about it we could have an iterator that returns q's sorted by the shortest path p->q. If you want a k nearest: iterator.take(k). If you want all in a range iterator.take_while(|p| p->q < range).

If you have some pointers I may be able to give this a try.

[easbar]

Ok yes the trivial way of doing this is calculating all paths p->q, then sorting by distance and taking only those up to some limit. Do you think this should be included here (it can easily be done using the existing API) ?

This can also be done more efficiently, but currently this is not supported. Btw in the context of routing networks this is sometimes called isochrone calculation.

[Eh2406]

Only when it can be done more efficiently than the alternatives. Do Contraction Hierarchies help make it more efficient than a Dijkstra's on an unprepared Graph? If so then yes it should be here. If not then I need talk to the pandana team about why they do it this way. :-P

[easbar]

Yes it can be more efficient. Even the trivial way we lined out above might be faster (on small maps at least).

why they do it this way

You mean they are doing this already ? How would implementing it here help with Pandana ?

[Eh2406]

It is a C++ python Library, it has in the past caused our entire model to segfault. I spent today trying to diagnose a regression in performance, our model is now taking an additional 16 hours to run. As someone who doesn't know C++... let's just say I would like the rust alternatives to be as ready to be a drop-in replacement as possible.