Comments (6)
I'm actually okay with exposing the innards of Type
. The only reason I haven't exposed it yet was just as a precaution in case I wanted to make internal changes to Type
without breaking API changes.
Before I do that, though, I just want to make sure it's necessary. There are ways to define new Interpret
instances without exposing the Type
internals by using the Functor
instance for type instead. Do you have an example of the type that you wanted to implement Interpret
for?
from dhall-haskell.
What do I need to do to get the instance Interpret (Map String String)
?
I'm trying to load "environment variables" like this from a config file:
{ HACKAGE_PASS="xxxx"
, HACKAGE_USER="xxxx"
, ...
}
These will be used to set up environment variables, and there can be any number of them.
from dhall-haskell.
@newhoggy: You can't load a Dhall record into a Haskell Map String String
, even if I exposed the internals of the Type
constructor. To see why, think about what the expected
field of the Type
would be
I would suggest that you should instead do one of the following two approaches:
-
If you know what the record fields will be ahead of time then load them into a Haskell record with matching fields, using Dhall's support for GHC generics, like this:
{-# LANGUAGE OverloadedStrings #-} {-# LANGUAGE DeriveAnyClass #-} {-# LANGUAGE DeriveGeneric #-} import Dhall data Config = Config { hackagePass :: Text , hackageUser :: Text } deriving (Generic, Interpret, Show) main :: IO () main = do x <- input auto "./example" print (x :: Config)
... with an input file like this:
{ hackagePass = "xxx" , hackageUser = "xxx" }
-
If some fields are going to be optional then make the Haskell record fields
Maybe
and the corresponding Dhall fieldsOptional
, like this:{-# LANGUAGE OverloadedStrings #-} {-# LANGUAGE DeriveAnyClass #-} {-# LANGUAGE DeriveGeneric #-} import Dhall data Config = Config { hackagePass :: Maybe Text , hackageUser :: Text } deriving (Generic, Interpret, Show) main :: IO () main = do x <- input auto "./example3" print (x :: Config)
... with an input file like this:
{ hackagePass = [] : Optional Text , hackageUser = "xxx" }
-
If you don't know what the fields will be ahead of time, then do this:
{-# LANGUAGE OverloadedStrings #-} {-# LANGUAGE DeriveAnyClass #-} {-# LANGUAGE DeriveGeneric #-} import Dhall data KeyVal = KeyVal { key :: Text, val :: Text } deriving (Generic, Interpret, Show) main :: IO () main = do x <- input auto "./example" print (x :: Vector KeyVal)
... with an input file like this:
[ { key = "HACKAGE_PASS" , val = "xxx" } , { key = "HACKAGE_USER" , val = "xxx" } ]
-
If you want the previous approach but you want to decode directly into a
Map Text Text
, then use theFunctor
instance forType
:{-# LANGUAGE OverloadedStrings #-} {-# LANGUAGE DeriveAnyClass #-} {-# LANGUAGE DeriveGeneric #-} {-# LANGUAGE RecordWildCards #-} import Data.Map (Map) import Dhall import qualified Data.Vector import qualified Data.Map data KeyVal = KeyVal { key :: Text, val :: Text } deriving (Generic, Interpret, Show) newtype Config = Config { keyVals :: Map Text Text } deriving (Show) instance Interpret Config where auto = fmap adapt0 auto where adapt0 = Config . Data.Map.fromList . fmap adapt1 . Data.Vector.toList where adapt1 (KeyVal {..}) = (key, val) main :: IO () main = do x <- input auto "./example" print (x :: Config)
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Perfect. Thanks!
from dhall-haskell.
You're welcome!
from dhall-haskell.
I'll go ahead and close this issue since I believe this has been answered
from dhall-haskell.
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