repeat execute JLToast.makeText().show about toaster

[devxoul]

@hengchengfei,
Could you please explain more detail to me?
Thanks.

[hengchengfei]

我的意思是，

连续点击弹出按钮，也就是连续调用JLToast.makeText()。

比如非常快的点击10次，会连续出来10个信息窗口。

而我希望在前一个弹出窗口还没消失的时候，不能再弹出窗口了。

但是我没发判断前一个窗口有没消失。

[hengchengfei]

repeat click the button，for example 10 times，then Toast view 10 times。

i want to show the next toast after the previous toast hide。

[devxoul]

Do you want 'hide previous toast and show new toast'?

[hengchengfei]

Yes

[devxoul]

That's not officially supported right now. (I'll make it as soon as possible)

However you can do with this:

previousToast.finish()
previousToast.view.removeFromSuperview()
// then show new toast

[uknowmeright]

here is some code that might help. It doesn't work in every situation but it might help you develop something fully functional:

`
var toasts = JLToast

func removeTheToast(toast: JLToast){
    for theToast in self.toasts{
        if theToast != toast {
            theToast.finish()
            theToast.view.removeFromSuperview()
        }
    }
}`


func showToast(string: String){
    let toast = JLToast.makeText(string.localized, duration: JLToastDelay.ShortDelay)
    toast.show()
    toasts.append(toast)
    removeTheToast(toast)
}

[devxoul]

Hey guys, thanks for waiting. #74 might help.