Comments (4)
I assume your scenario would be solved with the "variance" feature.
There's an experiment that allows writing code such as:
class Foo<in T> {}
class Bar<out T> {}
It adds extra restrictions on how a generic is used. I'm not familiar enough with the experiment, but I assume it could prevent assigning Task<int>
to Task<int?>
from language.
Greetings, I have also had similar problems, this has an explanation, it turns out that the T
type can sometimes behave like the Object
type. If we review the fundamentals, all the objects that exist inherit from the Object
class, this is equivalent to type Any
in Typescript therefore it is impossible to determine the type because it is too generic
My recommendation is to avoid at all using types that can be null, in case it is unavoidable use the Optional type to keep the null value wrapped and keep it controlled. I personally made a proposal to introduce the Optional type specifically for cases like this
from language.
That's "expected" I think.
int
is assignable to int?
. So Task<int>
is assignable to Task<int?>
.
Generics have a few gotchas, especially when we downcast a generic class.
A more common example would be:
List<Object?> list = <int>[]; // valid
// Technically valid too. String is an Object?
// But will throw at runtime.
list.add("string");
from language.
The issue here is not nullability, it's contravariance. As @rrousselGit says, the only real solution is the "variance" feature which allows a type parameter to be declared contravariant or invariant.
Until then, Dart's unsafe covariant generics allows you to write code that ends up calling a Task<int>.run
with null
, or a Task<int>.run
with 3.14
(by doing Task<num> task = Task<int>(); task.run(3.14);
with no nulls involved).
This is working as designed. There is no easy solution without introducing variance annotations. They'll happen if we can make them happen. It's non-trivial to add such declartions to existing code that wasn't written for them.
from language.
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from language.