Comments (5)
you can use TransFormer.urlEncodeMap(queryMap)
directly:
var queryMap={
'search': 'How to become a hero like LyNam'
};
var result = await dio.post('$url?${TransFormer.urlEncodeMap(queryMap)}',....);
from dio.
yes, we can process the string, but if dio can support, that will be simpler and safer by parse from URI in dio core
var uri = Uri.http('http://demo.com/api', '/search', {
'search': 'how can...'
});
it relate to baseUrl
and should be did in dio core.
from dio.
I known, you can also :
var uri=Uri(scheme: "https", host: "flutterchina.club", queryParameters: {
"xx":"xx",
"yy":"dd"
});
var result = await dio.post(uri.toString(),....)
I personally think that creating an Uri
instance is not easy and most of the time, the user has only a url link(String)。 so, dio
support url which type is String
default. when the users need an Uri
, they can also create it manually, and then call toString()
method to pass the result to the APIs of dio, It's very simple, isn't it。
from dio.
i remember i did like that, but the url be dupplicate with something like:
http://demo.com/http://demo.com/...........
i think dio has not handled full url like that yet.
ps: this i added baseurl to dio, and other case i have not done yet
from dio.
If the path
starts with "http:" or "https:", the baseUrl will be ignored. This feature will not be supported. Thanks !
from dio.
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