How is function2() working? what is this doing: Array.prototype.slice.call(arguments); ? about daily-coding-practice

[arc-arnob]

In the given code, Array.prototype.slice.call is used to convert the arguments object, which is an array-like object, into an actual array.

Here's how it works:
1. Array.prototype.slice is a built-in function of the Array object in JavaScript, which creates a new array from a given array-like object or array-like sequence.
2. In this case, Array.prototype.slice is being called with call() method to set the context of this keyword to arguments and slice method will create a new array from the arguments object.
3. Since the arguments object does not have all the methods available on an array, including the slice() method, we use call() to invoke the slice() method in the context of the arguments object.
4. The argsArray variable then gets assigned to the new array created by slice(), which is a copy of the arguments object.
5. Finally, the argsArray is logged to the console.

So, the output of the function function2(1, 2, 4) will be an array [1, 2, 4].